Advanced Computer Graphics

计算机绘图技术的编程及理论指导
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BSP TREE(occlusion culling)

(2005-05-06 01:59:53) 下一个

BSP树(1)

文档提供者:newebug () 于 2005-3-15

1 背景
BSP树1969年发明,90年代后用到游戏中。
BSP树是一个结构,可以分割为子集。BSP算法在pre-processing的时候处理多边形,而不是在run-time。
BSP树的结构定义如下:
class BSPTree
{
 BSPTreeNode RootNode
}
class BSPTreeNode
{
 BSPTree Tree
 BSPTreePolygon Divider
 BSPTreeNode *RightChild
 BSPTreeNode *LeftChild
 BSPTreePolygon PolygonSet[]
}
class BSPTreePolygon
{
 3DVector Point1
 3DVector Point2
 3DVector Point3
}

你可以将场景(scene)中的部分或全部的多边形(polygon)划分成一个个小集合(convex set),在这些集合中每个多边形都在其他任何多边形的前面。当polygon1中的所有点都在polygon2的前面的时候,我们说polygon1在polygon2的前面。

点在面前面的算法如下:
CLASSIFY-POINT (Polygon, Point)
SideValue = Polygon.Normal × Point
if (SideValue = Polygon.Distance)
 then return COINCIDING
else if (SideValue < Polygon.Distance)
 then return BEHIND
else return INFRONT

判断面在面前面的算法如下:
POLYGON-INFRONT (Polygon1, Polygon2)
for each point p in Polygon2
 if (CLASSIFY-POINT (Polygon1, p) <> INFRONT) then return false
return true

判断是否是一个convex set的算法如下:
IS-CONVEX-SET (PolygonSet)
for i = 0 to PolygonSet.Length ()
 for j = 0 to PolygonSet.Length ()
  if(i <> j && not POLYGON-INFRONT(PolygonSet[i], PolygonSet[j])) then return false
return true

判断多边形前后的算法如下:
CALCULATE-SIDE (Polygon1, Polygon2)
NumPositive = 0, NumNegative = 0
for each point p in Polygon2
 if (CLASSIFY-POINT (Polygon1, p) = INFRONT)
  then NumPositive = NumPositive + 1
 if (CLASSIFY-POINT (Polygon1, p) = BEHIND)
  then NumNegative = NumNegative + 1
if (NumPositive > 0 && NumNegative = 0)
 then return INFRONT
else if(NumPositive = 0 && NumNegative > 0)
 then return BEHIND
else if(NumPositive = 0 && NumNegative = 0)
 then return COINCIDING
else return SPANNING

上面的算法中,当返回SPANNING时,说明Polygon2跨越Polygon1,这时,一个通常的算法是将Polygon1分开成两个多边形。

有几个方法可以将场景中的多边形划分成所需要的BSP树,通常的办法是先定义一个多边形集合(convex set),然后在划分其他的。算法如下:
CHOOSE-DIVIDING-POLYGON (PolygonSet)
if( !IS-CONVEX-SET (PolygonSet) ) then return NOPOLYGON
MinRelation = MINIMUMRELATION
BestPolygon = NOPOLYGON
LeastSplits = INFINITY
BestRelation = 0

while(BestPolygon = NOPOLYGON)
 for each polygon P1 in PolygonSet
  if (Polygon P1 has not been used as divider previously during the creation of the tree)
   NumPositive = 0, NumNegative = 0, NumSpanning 0 0
   for each polygon P2 in PolygonSet except P1
    Value = CALCULATE-SIDE(P1, P2)
    if(Value = INFRONT)
     NumPositive = NumPositive + 1
    else if(Value = BEHIND)
     NumNegative = NumNegative + 1
    else if(Value = SPANNING)
     NumSpanning = NumSpanning + 1
   if (NumPositive < NumNegative)
    Relation = NumPositive / NumNegative
   else
    Relation = NumNegative / NumPositive
  if( (Relation > MinRelation) && (NumSpanning < LeastSplits) || (NumSpanning = LeastSplits) && (Relation > BestRelation) )
   BestPolygon = P1
   LeastSplits = NumSpanning
   BestRelation = Relation
  MinRelation = MinRelation / MINRELATIONSCALE
return BestPolygon

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